DxFileInput.UploadFile(UploadFileInfo) Method

Uploads the specified file.

Namespace: DevExpress.Blazor

Assembly: DevExpress.Blazor.v24.1.dll

NuGet Package: DevExpress.Blazor

Declaration

public void UploadFile(
    UploadFileInfo fileInfo
)

Parameters

Name	Type	Description
fileInfo	UploadFileInfo	The file to be uploaded.

Remarks

Note

UploadAllFiles, UploadFile, and UploadFiles methods ignore files whose upload processes failed or were canceled.

Once a user selects files in the Open dialog or drags files onto a drop zone, the File Input component adds these files to the file list. The file list displays each file’s upload status and upload, cancel, reload, and remove buttons. On the image below, the file list contains 4 files in different states:

Handle the SelectedFilesChanged event to access the collection of files in the file list. Call the following methods to manage these files in code:

	Start Upload	Cancel Upload	Restart Canceled Upload	Remove Files from List
One File	UploadFile	CancelFileUpload	ReloadFile	RemoveFile
Multiple Files	UploadFiles	CancelFilesUpload	ReloadFiles	RemoveFiles
All Files	UploadAllFiles	CancelAllFilesUpload	ReloadAllFiles	RemoveAllFiles

The following example displays a button that uploads the first file:

<DxFileInput @ref="MyFileInput"
             AllowMultiFileUpload="true"
             UploadMode="UploadMode.OnButtonClick"
             SelectedFilesChanged="@SelectedFilesChanged"
             FilesUploading="OnFilesUploading" />

<DxButton Text="Upload the First File" Click="OnUploadButtonClick" />

@code {
    DxFileInput MyFileInput { get; set; }
    IEnumerable<UploadFileInfo> Files { get; set; }

    protected void SelectedFilesChanged(IEnumerable<UploadFileInfo> files) {
        Files = files;
    }
    void OnUploadButtonClick() {
        if (Files != null)
            MyFileInput.UploadFile(Files.First());
    }
    async Task OnFilesUploading(FilesUploadingEventArgs args) {
        foreach (var file in args.Files) {
            /* The following code is intended for demonstration purposes only.
            Do not read a stream directly in memory to avoid performance and security-related issues. */
            using var stream = new System.IO.MemoryStream();
            await file.OpenReadStream(file.Size).CopyToAsync(stream);
        }
    }
}