FileUploadStartEventArgs.UploadUrl Property

Specifies a target URL for the upload request.

Namespace: DevExpress.Blazor

Assembly: DevExpress.Blazor.v23.2.dll

NuGet Package: DevExpress.Blazor

Declaration

public string UploadUrl { get; set; }

Property Value

Type	Description
String	The upload URL.

Remarks

Handle the FileUploadStart event to control file upload before it is started. Use the event argument’s FileInfo property to get information about the file (its name, type, size, and so on).

The Upload component’s UploadUrl property specifies a path of a server-side controller’s action that processes all the upload requests. Use the event argument’s UploadUrl property to change the controller action based on conditions. The snippet below changes the upload URL for PNG files.

Razor

<DxUpload Name="myFile" UploadUrl="https://localhost:10000/api/Upload/Upload/" 
          FileUploadStart="@OnFileUploadStart">
</DxUpload>

@code {
    void OnFileUploadStart(FileUploadStartEventArgs e) {
        if (e.FileInfo.Type == "image/png")
            e.UploadUrl = "https://localhost:10000/api/Upload/UploadPng/";
    }
}

UploadController

using System.IO;
using System.Linq;
using Microsoft.AspNetCore.Hosting;
using Microsoft.AspNetCore.Http;
using Microsoft.AspNetCore.Mvc;

[Route("api/[controller]")]
public class UploadController : ControllerBase {
    private readonly IWebHostEnvironment _hostingEnvironment;

    public UploadController(IWebHostEnvironment hostingEnvironment) {
        _hostingEnvironment = hostingEnvironment;
    }

    [HttpPost]
    [Route("UploadFile")]
    public ActionResult UploadFile(IFormFile myFile) {
        // ...
    }

    [HttpPost]
    [Route("UploadPng")]
    public ActionResult UploadPng(IFormFile myFile) {
        try {
            var path = Path.Combine(_hostingEnvironment.WebRootPath, "images");
            if (!Directory.Exists(path))
                Directory.CreateDirectory(path);
            using (var fileStream = System.IO.File.Create(Path.Combine(path, myFile.FileName))) {
                myFile.CopyTo(fileStream);
            }
        } catch {
            Response.StatusCode = 400;
        }
        return new EmptyResult();
    }
}