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V24.1

XtraInputBox.Show<T>(String, String, T, XtraInputBox.Buttons) Method

Displays an input box with the specified settings.

Namespace: DevExpress.XtraEditors

Assembly: DevExpress.XtraEditors.v24.1.dll

NuGet Package: DevExpress.Win.Navigation

Declaration

public static T? Show<T>(
    string prompt,
    string title,
    T defaultResponse,
    XtraInputBox.Buttons buttons
)
    where T : struct

Parameters

Name Type Description
prompt String

The text string displayed above an Input Box editor.

title String

The Input Box window caption.

defaultResponse T

The initial editor value.

buttons XtraInputBox.Buttons

Specifies Input Box buttons.

Type Parameters

Name Description
T

The type of a value requested from users.

Returns

Type Description
Nullable<T>

The value entered by a user, or null if nothing was entered.

Remarks

The code below illustrates how to invoke an XtraInputBox with a DateEdit editor.

XtraInputBox.Show("Select a date", "Jump to Date", DateTime.Now, Buttons.OKCancel);

You can also use XtraInputBoxArgs objects to pass required Input Box settings.

The code snippet below shows how to display a dialog box with custom settings.

using DevExpress.XtraEditors;

// Display an iput box with the specifiedx prompt, title, and default response.
XtraInputBox.Show("Enter a new value", "Change Settings", "Default");
XtraInputBox.Show(this, "Enter a new value", "Change Settings", "Default");

// Initialize a new XtraInputBoxArgs instance.
XtraInputBoxArgs args = new XtraInputBoxArgs();
// Specify settings.
args.Caption = "Shipping options";
args.Prompt = "Delivery date";
args.DefaultButtonIndex = 0;
// Initialize a new DateEdit instance.
DateEdit editor = new DateEdit();
// Specify settings.
editor.Properties.CalendarView = DevExpress.XtraEditors.Repository.CalendarView.TouchUI;
editor.Properties.Mask.EditMask = "MMMM d, yyyy";
// Assign the editor to the input box settings.
args.Editor = editor;
// Specify the editor's default value.
args.DefaultResponse = DateTime.Now.Date.AddDays(3);
// Display an input box and assign the result to a variable.
var result = XtraInputBox.Show(args);

// You can also use the generic method and specify the return value's type.
DateTime resultDateTime = XtraInputBox.Show<DateTime>(args);
See Also