BingItineraryItem.Distance Property

Gets the distance of the itinerary item.

Namespace: DevExpress.Xpf.Map

Assembly: DevExpress.Xpf.Map.v25.1.dll

NuGet Package: DevExpress.Wpf.Map

Declaration

C#

public double Distance { get; }

VB.NET

Public ReadOnly Property Distance As Double

Property Value

Type	Description
Double	A Double value specifying the item distance.

Example

MainWindow.xaml.cs

string ProcessItinerary(List<BingItineraryItem> items) {
    if (items == null) return "";

    StringBuilder sb = new StringBuilder("\tInternary Items:\n");
    for (int i = 0; i < items.Count; i++) {
        sb.Append(String.Format("\t\tItinerary {0}:\n", i+1));
        sb.Append(String.Format("\t\tManeuver: {0}\n", items[i].Maneuver));
        sb.Append(String.Format("\t\tLocation: {0}\n", items[i].Location));
        sb.Append(String.Format("\t\tInstructions: {0}\n", items[i].ManeuverInstruction));
        sb.Append(ProcessWarnings(items[i].Warnings));
    }
    return sb.ToString();
}

MainWindow.xaml.vb

Private Function ProcessItinerary(ByVal items As List(Of BingItineraryItem)) As String
    If items Is Nothing Then
        Return ""
    End If

    Dim sb As New StringBuilder(ControlChars.Tab & "Internary Items:" & ControlChars.Lf)
    For i As Integer = 0 To items.Count - 1
        sb.Append(String.Format(ControlChars.Tab & ControlChars.Tab & "Itinerary {0}:" & ControlChars.Lf, i+1))
        sb.Append(String.Format(ControlChars.Tab & ControlChars.Tab & "Maneuver: {0}" & ControlChars.Lf, items(i).Maneuver))
        sb.Append(String.Format(ControlChars.Tab & ControlChars.Tab & "Location: {0}" & ControlChars.Lf, items(i).Location))
        sb.Append(String.Format(ControlChars.Tab & ControlChars.Tab & "Instructions: {0}" & ControlChars.Lf, items(i).ManeuverInstruction))
        sb.Append(ProcessWarnings(items(i).Warnings))
    Next i
    Return sb.ToString()
End Function