TreeListView.GetNodeByRowHandle(Int32) Method

Returns a node with the specified handle.

Namespace: DevExpress.Xpf.Grid

Assembly: DevExpress.Xpf.Grid.v22.2.dll

NuGet Package: DevExpress.Wpf.Grid.Core

Declaration

C#

public TreeListNode GetNodeByRowHandle(
    int rowHandle
)

VB.NET

Public Function GetNodeByRowHandle(
    rowHandle As Integer
) As TreeListNode

Parameters

Name	Type	Description
rowHandle	Int32	An integer value that specifies the row handle.

Returns

Type	Description
TreeListNode	A TreeListNode object that is the node with the specified handle. null (Nothing in Visual Basic) if the node was not found.

Remarks

The GetNodeByRowHandle method returns the node whose TreeListNodeBase.RowHandle property is set to a value specified by the rowHandle parameter.

To learn more, see Obtaining Nodes.

Related GitHub Examples

The following code snippet (auto-collected from DevExpress Examples) contains a reference to the GetNodeByRowHandle(Int32) method.

Note

The algorithm used to collect these code examples remains a work in progress. Accordingly, the links and snippets below may produce inaccurate results. If you encounter an issue with code examples below, please use the feedback form on this page to report the issue.

C#

dxtreelist-how-to-implement-summary-footers-e4793/CS/MyTreeListView.xaml.cs#L164

public bool IsLastRowInGroup(int groupRowHandle) {
    TreeListNode node = View.GetNodeByRowHandle(groupRowHandle);
    int maxHandle = 0;

VB.NET

dxtreelist-how-to-implement-summary-footers-e4793/VB/MyTreeListView.xaml.vb#L205

Public Function IsLastRowInGroup(ByVal groupRowHandle As Integer) As Boolean
    Dim node As TreeListNode = View.GetNodeByRowHandle(groupRowHandle)
    Dim maxHandle As Integer = 0