TreeListView.GetNodeVisibleIndex(TreeListNode) Method

Returns the node’s position within a View among visible nodes.

Namespace: DevExpress.Xpf.Grid

Assembly: DevExpress.Xpf.Grid.v24.2.dll

NuGet Package: DevExpress.Wpf.Grid.Core

Declaration

C#

public int GetNodeVisibleIndex(
    TreeListNode node
)

VB.NET

Public Function GetNodeVisibleIndex(
    node As TreeListNode
) As Integer

Parameters

Name	Type	Description
node	TreeListNode	A TreeListNode object that is the node whose visible index is returned.

Returns

Type	Description
Int32	An integer value that specifies the node’s position among visible nodes. -1 if the specified node is hidden.

Remarks

To obtain a node by its visible index, use the TreeListView.GetNodeByVisibleIndex method.

To learn more, see Obtaining Nodes.