TreeListView.GetNodeVisibleIndex(TreeListNode) Method
In This Article
Returns the node’s position within a View among visible nodes.
Namespace: DevExpress.Xpf.Grid
Assembly: DevExpress.Xpf.Grid.v24.2.dll
NuGet Package: DevExpress.Wpf.Grid.Core
#Declaration
public int GetNodeVisibleIndex(
TreeListNode node
)
#Parameters
Name | Type | Description |
---|---|---|
node | Tree |
A Tree |
#Returns
Type | Description |
---|---|
Int32 | An integer value that specifies the node’s position among visible nodes. -1 if the specified node is hidden. |
#Remarks
To obtain a node by its visible index, use the TreeListView.GetNodeByVisibleIndex method.
To learn more, see Obtaining Nodes.
See Also