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TreeListView.GetNodeVisibleIndex(TreeListNode) Method

Returns the node’s position within a View among visible nodes.

Namespace: DevExpress.Xpf.Grid

Assembly: DevExpress.Xpf.Grid.v24.2.dll

NuGet Package: DevExpress.Wpf.Grid.Core

#Declaration

public int GetNodeVisibleIndex(
    TreeListNode node
)

#Parameters

Name Type Description
node TreeListNode

A TreeListNode object that is the node whose visible index is returned.

#Returns

Type Description
Int32

An integer value that specifies the node’s position among visible nodes. -1 if the specified node is hidden.

#Remarks

To obtain a node by its visible index, use the TreeListView.GetNodeByVisibleIndex method.

To learn more, see Obtaining Nodes.

See Also