TreeListView.GetNodeByVisibleIndex(Int32) Method
In This Article
Returns a node with the specified visible index.
Namespace: DevExpress.Xpf.Grid
Assembly: DevExpress.Xpf.Grid.v24.2.dll
NuGet Package: DevExpress.Wpf.Grid.Core
#Declaration
public TreeListNode GetNodeByVisibleIndex(
int visibleIndex
)
#Parameters
Name | Type | Description |
---|---|---|
visible |
Int32 | An integer value that specifies the node’s position within a View. |
#Returns
Type | Description |
---|---|
Tree |
A Tree |
#Remarks
To learn more, see Obtaining Nodes.
See Also