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DataControlBase.ColumnGeneratorTemplate Property

Gets or sets a template that describes grid columns. This is a dependency property.

Namespace: DevExpress.Xpf.Grid

Assembly: DevExpress.Xpf.Grid.v22.1.Core.dll

NuGet Package: DevExpress.Wpf.Grid.Core

Declaration

public DataTemplate ColumnGeneratorTemplate { get; set; }

Property Value

Type Description
DataTemplate

The column template.

Remarks

You can define columns in a ViewModel and display them in the GridControl. To do this, follow the steps below:

  1. Create a collection of grid columns in a ViewModel.
  2. Specify a data template that generates columns:

    <Window.Resources>
        <DataTemplate x:Key="DefaultColumnTemplate">
            <dxg:GridColumn FieldName="{Binding Path=(dxci:DependencyObjectExtensions.DataContext).FieldName, RelativeSource={RelativeSource Self}}"/>
        </DataTemplate>
    </Window.Resources>
    
  3. Assign the column collection to the ColumnsSource property and the column template to the ColumnGeneratorTemplate property:

    <dxg:GridControl ...
                     ColumnsSource="{Binding Columns}" 
                     ColumnGeneratorTemplate="{StaticResource DefaultColumnTemplate}"/>
    

If you have multiple column templates, use the ColumnGeneratorTemplateSelector property to specify a template selector that chooses a template based on a column type.

Refer to the following help topic for more information: How to: Bind the Grid to a Collection of Columns.

See Also