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ASPxClientPopupControl.ShowWindowAtElement(window, htmlElement) Method

Invokes the popup control’s specific window and displays it over the specified HTML element.

#Declaration

TypeScript
ShowWindowAtElement(
    window: ASPxClientPopupWindow,
    htmlElement: any
): void

#Parameters

Name Type Description
window ASPxClientPopupWindow

A ASPxClientPopupWindow object representing the popup window to display.

htmlElement any

An object specifying the HTML element relative to whose position the default popup window is invoked.

#Remarks

Use the ShowWindowAtElement method on the client side to display a popup window specified by the window parameter at a position which relates to an HTML element specified by the htmlElement parameter. For instance, this method can be used when it’s necessary to display a popup window in response to a specific user action not listed by the ASPxPopupControl.PopupAction property or over a specific HTML element that differs from the element specified by the ASPxPopupControl.PopupElementID (or PopupWindow.PopupElementID) property.

A call to the ShowWindowAtElement method displays the specified popup window at a position defined by the ASPxPopupControl.PopupHorizontalAlign, ASPxPopupControl.PopupHorizontalOffset, ASPxPopupControl.PopupVerticalAlign and ASPxPopupControl.PopupVerticalOffset properties relative to the specified HTML element.

See Also