Skip to main content

ASPxClientPopupControlBase.ShowAtElement(htmlElement) Method

Invokes the control’s window and displays it over the specified HTML element.

#Declaration

TypeScript
ShowAtElement(
    htmlElement: any
): void

#Parameters

Name Type Description
htmlElement any

An object specifying the HTML element relative to whose position the window is invoked.

#Remarks

Use the ShowAtElement method on the client side, to display the control’s window at a position which relates to an HTML element specified by the htmlElement parameter.

Note

For ASPxPopupControl only:

This method can be used, for example, when it’s necessary to display the window in response to a specific user action not listed by the ASPxPopupControl.PopupAction property or over a specific HTML element that differs from the element specified by the ASPxPopupControl.PopupElementID property.

A call to the ShowAtElement method displays the default popup window at a position specified by the ASPxPopupControl.PopupHorizontalAlign, ASPxPopupControl.PopupHorizontalOffset, ASPxPopupControl.PopupVerticalAlign and ASPxPopupControl.PopupVerticalOffset properties relative to the specified HTML element.

See Also