JsonNode Class

Defines a node in the JsonDataSource‘s schema.

Namespace: DevExpress.DataAccess.Json

Assembly: DevExpress.DataAccess.v24.2.dll

Declaration

C#

public class JsonNode

VB.NET

Public Class JsonNode

Remarks

Use the JsonSchemaNode.Value property to access a JsonNode class instance and its members.

The following properties specify a JSON schema node:

• Name - the node name.
• DisplayName - the node’s display name.
• Type - the data source field type.
• NodeType - specifies if the node is an array, object, or property.
• Selected - specifies whether to include the node in the JSON schema.

Example

The code sample below defines the JSON data source schema that consists of the Customer ID and CompanyName fields.

C#

using DevExpress.DataAccess.Json;
// ...
// Define the data source schema.
var root = new JsonSchemaNode();
root.NodeType = JsonNodeType.Object;
var customers = new JsonSchemaNode() { NodeType=JsonNodeType.Array, Name="Customers", Selected=true};
customers.AddChildren(new[] {
    new JsonSchemaNode(new JsonNode("ID", true, JsonNodeType.Property, typeof(string))) { DisplayName="Customer ID"},
    new JsonSchemaNode() { Name="CompanyName", Selected=true, NodeType=JsonNodeType.Property, Type=typeof(string)},
});
root.AddChildren(customers);

VB.NET

Imports DevExpress.DataAccess.Json
' ...
' Define the data source schema.
Dim root = New JsonSchemaNode()
root.NodeType = JsonNodeType.Object
Dim customers = New JsonSchemaNode() With {.NodeType = JsonNodeType.Array, .Name = "Customers", .Selected = True}
customers.AddChildren({
    New JsonSchemaNode(New JsonNode("ID", True, JsonNodeType.Property, GetType(String))) With {.DisplayName = "Customer ID"},
    New JsonSchemaNode() With {.Name = "CompanyName", .Selected = True, .NodeType = JsonNodeType.Property, .Type = GetType(String)}
})
root.AddChildren(customers)

Inheritance

Object

JsonNode