CriteriaOperator.FromLambda<TModel, TResult>(Expression<Func<TModel, TResult>>) Method

Converts the specified LINQ-like expression to its CriteriaOperator equivalent.

Namespace: DevExpress.Data.Filtering

Assembly: DevExpress.Data.v23.2.dll

NuGet Package: DevExpress.Data

Declaration

C#

public static CriteriaOperator FromLambda<TModel, TResult>(
    Expression<Func<TModel, TResult>> lambda
)

VB.NET

Public Shared Function FromLambda(Of TModel, TResult)(
    lambda As Expression(Of Func(Of TModel, TResult))
) As CriteriaOperator

Parameters

Name	Type	Description
lambda	Expression<Func<TModel, TResult>>	A LINQ expression to convert.

Type Parameters

Name	Description
TModel	A type of object to which the expression is applied.
TResult	A type of object that is returned by the converted expression.

Returns

Type	Description
CriteriaOperator	A CriteriaOperator equivalent to the expression passed to the method’s parameter.

Remarks

Use the FromLambda method to create a criteria operator from a LINQ-like predicate expression:

C#

// Returns "[Name]"
CriteriaOperator stringCriteria = CriteriaOperator.FromLambda<User,string>(u => u.Name);
// Returns "[Departments].Single()"
CriteriaOperator classCriteria = CriteriaOperator.FromLambda<User, Department>(u => u.Departments.SingleOrDefault());

VB.NET

' Returns "[Name]"
Dim stringCriteria As CriteriaOperator = CriteriaOperator.FromLambda(Of User, String) _
    (Function(u) u.Name)
' Returns "[Departments].Single()"
Dim classCriteria As CriteriaOperator = CriteriaOperator.FromLambda(Of User, Department) _
    (Function(u) u.Departments.SingleOrDefault()) 

Tip

For information on how to build LINQ-like expressions, refer to the following topic: LINQ-Like Criteria Syntax