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ASPxClientPopupMenu.ShowAtElement(htmlElement) Method

Invokes the popup menu and displays it over the specified HTML element.

#Declaration

TypeScript
ShowAtElement(
    htmlElement: any
): void

#Parameters

Name Type Description
htmlElement any

An object specifying the HTML element relative to which position the popup menu is invoked.

#Remarks

Use the ShowAtElement method on the client side to display the popup menu at a position which relates to an HTML element specified by the htmlElement parameter. This method can be used, for example, when it’s necessary to display the popup menu in response to a specific user action not listed by the ASPxPopupMenu.PopupAction property, or over a specific HTML element that differs from the element specified by the ASPxPopupMenu.PopupElementID property.

A call to the ShowAtElement method displays the popup menu at a position specified by the ASPxPopupMenu.PopupHorizontalAlign, ASPxPopupMenu.PopupHorizontalOffset, ASPxPopupMenu.PopupVerticalAlign and ASPxPopupMenu.PopupVerticalOffset properties relative to the specified HTML element.

See Also