OfficeImage.GetContentType(OfficeImageFormat) Method

Static method used to get the MIME content type by the OfficeImageFormat value.

Namespace: DevExpress.Office.Utils

Assembly: DevExpress.Office.v24.2.Core.dll

NuGet Package: DevExpress.Office.Core

Declaration

C#

[ComVisible(false)]
public static string GetContentType(
    OfficeImageFormat imageFormat
)

VB.NET

<ComVisible(False)>
Public Shared Function GetContentType(
    imageFormat As OfficeImageFormat
) As String

Parameters

Name	Type	Description
imageFormat	OfficeImageFormat	An OfficeImageFormat enumeration member specifying the image format.

Returns

Type	Description
String	A string indicating the mime content type.

Remarks

The GetContentType method enables you to obtain the standard MIME type associated with a given XtraRichEdit image format. For example, the OfficeImageFormat.Emf corresponds to the “application/x-msmetafile” MIME type.

This method can be helpful in constructing an HTML page markup.

Related GitHub Examples

The following code snippet (auto-collected from DevExpress Examples) contains a reference to the GetContentType(OfficeImageFormat) method.

Note

The algorithm used to collect these code examples remains a work in progress. Accordingly, the links and snippets below may produce inaccurate results. If you encounter an issue with code examples below, please use the feedback form on this page to report the issue.

C#

build-a-mail-application-with-the-richeditcontrol/CS/RichEditSendMail/Form1.cs#L113

Stream stream = new MemoryStream(image.GetImageBytes(imageFormat));
string mediaContentType = OfficeImage.GetContentType(imageFormat);
AttachementInfo info = new AttachementInfo(stream, mediaContentType, imageName);

VB.NET

build-a-mail-application-with-the-richeditcontrol/VB/RichEditSendMail/Form1.vb#L105

Dim stream As Stream = New MemoryStream(image.GetImageBytes(imageFormat))
Dim mediaContentType As String = OfficeImage.GetContentType(imageFormat)
Dim info As AttachementInfo = New AttachementInfo(stream, mediaContentType, imageName)