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V25.1
  • IReportDesignerModelBuilder.BuildJsonModel() Method

    Builds a View Model for a Report Designer component and serializes the model to JSON.

    Namespace: DevExpress.XtraReports.Web.ReportDesigner.Services

    Assembly: DevExpress.XtraReports.v25.1.Web.dll

    NuGet Package: DevExpress.Web.Reporting.Common

    Declaration

    string BuildJsonModel()

    Returns

    Type Description
    String

    A string that is the JSON-serialized model.

    Remarks

    The following code example is a controller that builds and returns the client-side model to an Angular client app:

    [ApiController]
    [Authorize]
    [Route("api/[controller]")]
    public class ReportDesignerSetupController : ControllerBase {
        [HttpPost("[action]")]
        public object GetReportDesignerModel([FromForm] string reportUrl,
            [FromServices] IReportDesignerModelBuilder reportDesignerModel,
            [FromServices] IReportDesignerClientSideModelGenerator modelGenerator) {
            Dictionary<string, object> dataSources = new Dictionary<string, object>();
            //Fill a data source set if needed
            reportDesignerModel
                .Report(reportUrl)
                .DataSources(dataSources)
                .DesignerUri("/DXXRDAngular")
                .ViewerUri("/DXXRDVAngular")
                .QueryBuilderUri("/DXXQBAngular")
                .BuildJsonModel();
            var model = reportDesignerModel.BuildModel();
            var modelJson = modelGenerator.GetJsonModelScript(model);
            return Content(modelJson, MediaTypeNames.Application.Json);
        }
    }
    

    View Example

    See Also