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SpreadsheetBuilder.Open(String, DocumentFormat, Func<Stream>) Method

Opens a document in the specified format from a stream.

Namespace: DevExpress.AspNetCore.Spreadsheet

Assembly: DevExpress.AspNetCore.Spreadsheet.v24.1.dll

NuGet Package: DevExpress.AspNetCore.Spreadsheet

Declaration

public SpreadsheetBuilder Open(
    string documentId,
    DocumentFormat documentFormat,
    Func<Stream> contentAccessorByStream
)

Parameters

Name Type Description
documentId String

A document identifier.

documentFormat DocumentFormat

A document format.

contentAccessorByStream Func<Stream>

A method delegate that obtains a stream.

Returns

Type Description
SpreadsheetBuilder

An object that can be used to further configure the Spreadsheet.

Remarks

This method overload allows you to disable automatic format detection and improve performance when the Spreadsheet opens a document. Call the Open(String, Func<Stream>) method to determine the document’s format automatically when you open a document. Refer to the following section for more information: Open a Document from a Stream.

The example below demonstrates how to open a document from a stream:

@model SpreadsheetDocumentContent

@(Html.DevExpress()
    .Spreadsheet("spreadsheet")
    .Open(@Model.DocumentId, DocumentFormat.Xlsx, @Model.ContentAccessorByStream)
)
public IActionResult Index() {
    Func<Stream> contentAccessorByStream = () => System.IO.File.Open("your-file-path", FileMode.Open);
    var model = new SpreadsheetDocumentContent(DocumentId1, contentAccessorByStream);
    return View(model);
}
public class SpreadsheetDocumentContent {
    public string DocumentId { get; set; }
    public Func<Stream> ContentAccessorByStream { get; set; }
    public DocumentFormat DocumentFormat { get; set; } = DocumentFormat.Xlsx;
    public SpreadsheetDocumentContent(string documentId, Stream contentAccessorByStream) {
        DocumentId = documentId;
        ContentAccessorByStream = contentAccessorByStream;
    }
}
See Also