GridSplitContainer.SplitterPosition Property

Gets or sets the splitter’s location.

Namespace: DevExpress.XtraGrid

Assembly: DevExpress.XtraGrid.v18.2.dll

Declaration

C#

[DXCategory("Layout")]
[DefaultValue(0)]
public override int SplitterPosition { get; set; }

VB.NET

<DXCategory("Layout")>
<DefaultValue(0)>
Public Overrides Property SplitterPosition As Integer

Property Value

Type	Default	Description
Int32	0	An integer value specifying the splitter’s current location in pixels

Related GitHub Examples

The following code snippets (auto-collected from DevExpress Examples) contain references to the SplitterPosition property.

Note

The algorithm used to collect these code examples remains a work in progress. Accordingly, the links and snippets below may produce inaccurate results. If you encounter an issue with code examples below, please use the feedback form on this page to report the issue.

C#

how-to-provide-the-capability-to-create-fixed-rows-in-the-gridview-e3045/CS/SplitDescendantWithExtension/FixedRowsExtension.cs#L79

GridViewInfo viewInfo1 = gridViewPanel1.GetViewInfo() as GridViewInfo;
gridSplitContainer1.SplitterPosition = viewInfo1.ViewRects.ColumnPanel.Bottom;
GridViewInfo viewInfo2 = gridViewPanel2.GetViewInfo() as GridViewInfo;

how-to-pin-the-new-item-row-to-the-gridview-bottom-e4910/CS/Grid_BottomNewItemRow/BottomNewItemRowEx.cs#L76

_Container.SplitterPosition = newSplitterPosition;

VB.NET

how-to-provide-the-capability-to-create-fixed-rows-in-the-gridview-e3045/VB/SplitDescendantWithExtension/FixedRowsExtension.vb#L206

End If
gridSplitContainer1.SplitterPosition = splitterPosition
splitterPosition -= viewInfo.ViewRects.EmptyRows.Bottom - viewInfo.ViewRects.EmptyRows.Top

how-to-pin-the-new-item-row-to-the-gridview-bottom-e4910/VB/Grid_BottomNewItemRow/BottomNewItemRowEx.vb#L70

_Container.SplitterPosition = newSplitterPosition