UriJsonSource.Uri Property
Gets or sets the System.Uri object that points to a URI or text file with JSON data.
Namespace: DevExpress.DataAccess.Json
Assembly: DevExpress.DataAccess.v21.1.dll
NuGet Packages: DevExpress.DataAccess, DevExpress.Win.Design
Declaration
Property Value
Type | Default | Description |
---|---|---|
Uri | *null* | Points to a Web-service endpoint or text file with JSON data. |
Remarks
The following example demonstrates how to associate the JsonDataSource object with data from a web-service endpoint.
using DevExpress.DataAccess.Json;
using DevExpress.XtraReports.UI;
public static JsonDataSource CreateDataSourceFromWeb() {
var jsonDataSource = new JsonDataSource();
// Specify the endpoint.
jsonDataSource.JsonSource = new UriJsonSource(new Uri("https://raw.githubusercontent.com/DevExpress-Examples/DataSources/master/JSON/customers.json"));
var root = new JsonSchemaNode();
root.NodeType = JsonNodeType.Object;
var customers = new JsonSchemaNode() {NodeType=JsonNodeType.Array, Name="Customers", Selected=true };
customers.AddChildren(new[] {
new JsonSchemaNode(new JsonNode("CustomerID", true, JsonNodeType.Property, typeof(string))) { DisplayName = "Customer ID" },
new JsonSchemaNode() {
Name = "CompanyName",
Selected = true,
NodeType = JsonNodeType.Property,
Type = typeof(string)
},
new JsonSchemaNode(new JsonNode("ContactTitle", true, JsonNodeType.Property, typeof(string))),
new JsonSchemaNode(new JsonNode("Address", false, JsonNodeType.Property, typeof(string)))
});
root.AddChildren(customers);
jsonDataSource.Schema = root;
// Populate the data source with data.
jsonDataSource.Fill();
return jsonDataSource;
}
The following example demonstrates how to associate the JsonDataSource object with JSON data from a file.
using DevExpress.DataAccess.Json;
using DevExpress.XtraReports.UI;
public static JsonDataSource CreateDataSourceFromFile() {
var jsonDataSource = new JsonDataSource();
// Specify the JSON file name.
Uri fileUri = new Uri("customers.json", UriKind.RelativeOrAbsolute);
jsonDataSource.JsonSource = new UriJsonSource(fileUri);
// Populate the data source with data.
jsonDataSource.Fill();
return jsonDataSource;
}
See Also