BingRouteLeg.EndPoint Property

Gets the end point of this route leg.

Namespace: DevExpress.Xpf.Map

Assembly: DevExpress.Xpf.Map.v25.1.dll

NuGet Package: DevExpress.Wpf.Map

Declaration

C#

public GeoPoint EndPoint { get; }

VB.NET

Public ReadOnly Property EndPoint As GeoPoint

Property Value

Type	Description
GeoPoint	A GeoPoint object.

Example

MainWindow.xaml.cs

string ProcessLegs(List<BingRouteLeg> legs) {
    if (legs == null) return "";

    StringBuilder sb = new StringBuilder("Legs:\n");    
    for (int i = 0; i < legs.Count; i++) {
        sb.Append(String.Format("\tLeg {0}:\n", i+1));
        sb.Append(String.Format("\tStart: {0}\n", legs[i].StartPoint));
        sb.Append(String.Format("\tEnd: {0}\n", legs[i].EndPoint));
        sb.Append(String.Format("\tDistance: {0}\n", legs[i].Distance));
        sb.Append(String.Format("\tTime: {0}\n", legs[i].Time));
        sb.Append(ProcessItinerary(legs[i].Itinerary));
    }
    return sb.ToString();
}

MainWindow.xaml.vb

Private Function ProcessLegs(ByVal legs As List(Of BingRouteLeg)) As String
    If legs Is Nothing Then
        Return ""
    End If

    Dim sb As New StringBuilder("Legs:" & ControlChars.Lf)
    For i As Integer = 0 To legs.Count - 1
        sb.Append(String.Format(ControlChars.Tab & "Leg {0}:" & ControlChars.Lf, i+1))
        sb.Append(String.Format(ControlChars.Tab & "Start: {0}" & ControlChars.Lf, legs(i).StartPoint))
        sb.Append(String.Format(ControlChars.Tab & "End: {0}" & ControlChars.Lf, legs(i).EndPoint))
        sb.Append(String.Format(ControlChars.Tab & "Distance: {0}" & ControlChars.Lf, legs(i).Distance))
        sb.Append(String.Format(ControlChars.Tab & "Time: {0}" & ControlChars.Lf, legs(i).Time))
        sb.Append(ProcessItinerary(legs(i).Itinerary))
    Next i
    Return sb.ToString()
End Function