TreeList.GetNodeByVisibleIndex(Int32) Method

Returns a node with the specified index among the visible nodes.

Namespace: DevExpress.XtraTreeList

Assembly: DevExpress.XtraTreeList.v23.2.dll

NuGet Packages: DevExpress.Win.Navigation, DevExpress.Win.TreeList

Declaration

C#

public TreeListNode GetNodeByVisibleIndex(
    int index
)

VB.NET

Public Function GetNodeByVisibleIndex(
    index As Integer
) As TreeListNode

Parameters

Name	Type	Description
index	Int32	A zero-based integer specifying the node’s index.

Returns

Type	Description
TreeListNode	A TreeListNode object representing the node with the specified index. null (Nothing in Visual Basic) if the node with the specified index is not found.

Related GitHub Examples

The following code snippet (auto-collected from DevExpress Examples) contains a reference to the GetNodeByVisibleIndex(Int32) method.

Note

The algorithm used to collect these code examples remains a work in progress. Accordingly, the links and snippets below may produce inaccurate results. If you encounter an issue with code examples below, please use the feedback form on this page to report the issue.

C#

winforms-treelist-save-restore-expanded-state-of-nodes/CS/TreeListViewState.cs#L69

    focused = TreeList.FocusedNode[TreeList.KeyFieldName];
    topNode = TreeList.GetNodeByVisibleIndex(TreeList.TopVisibleNodeIndex)[TreeList.KeyFieldName];
}

VB.NET

winforms-treelist-save-restore-expanded-state-of-nodes/VB/TreeListViewState.vb#L76

    focused = TreeList.FocusedNode(TreeList.KeyFieldName)
    topNode = TreeList.GetNodeByVisibleIndex(TreeList.TopVisibleNodeIndex)(TreeList.KeyFieldName)
Else