CardView(GridControl) Constructor

Creates a new CardView object with the specified owner.

Namespace: DevExpress.XtraGrid.Views.Card

Assembly: DevExpress.XtraGrid.v19.2.dll

Declaration

C#

public CardView(
    GridControl ownerGrid
)

VB.NET

Public Sub New(
    ownerGrid As GridControl
)

Parameters

Name	Type	Description
ownerGrid	GridControl	A GridControl object representing a grid control that will own the created View. This value is assigned to the BaseView.GridControl property.

Remarks

You can use the created View in a number of ways. For instance, assign it to the grid’s GridControl.MainView property, add it to the GridControl.LevelTree tree or use it within the master-detail events provided by the XtraGrid.

Before using a View within the Grid Control ensure that its BaseView.GridControl property has been initialized. For Views created at design time this property is initialized automatically. If a View is assigned to the GridControl.MainView property its BaseView.GridControl property is also initialized automatically. In all other cases the BaseView.GridControl property should be set manually.

Related GitHub Examples

The following code snippet (auto-collected from DevExpress Examples) contains a reference to the CardView(GridControl) constructor.

Note

The algorithm used to collect these code examples remains a work in progress. Accordingly, the links and snippets below may produce inaccurate results. If you encounter an issue with code examples below, please use the feedback form on this page to report the issue.

VB.NET

how-to-create-a-cardview-descendant-class-and-register-it-for-design-time-use-t122333/VB/MyCardView/MyCardView.vb#L14

Public Sub New(ByVal ownerGrid As DevExpress.XtraGrid.GridControl)
    MyBase.New(ownerGrid)
    ' put your initialization code here