XtraInputBox.Show(IWin32Window, String, String, String, MessageBoxButtons) Method

Displays an input box with the specified title, prompt, default response, and buttons. You can also specify the window that provides look and feel settings for the input box.

Namespace: DevExpress.XtraEditors

Assembly: DevExpress.XtraEditors.v21.2.dll


public static string Show(
    IWin32Window owner,
    string prompt,
    string title,
    string defaultResponse,
    MessageBoxButtons buttons


Name Type Description
owner IWin32Window

An IWin32Window object that provides look and feel settings for the dialog box.

prompt String

The text above the editor.

title String

The text in the title bar.

defaultResponse String

The text that is the editor’s default value.

buttons MessageBoxButtons

A value that specifies which buttons to display in the input box.


Type Description

If OK or Yes is clicked, the editor’s value. Otherwise, String.Empty.


The code snippet below shows how to display a dialog box with custom settings.

using DevExpress.XtraEditors;

// Display an iput box with the specifiedx prompt, title, and default response.
XtraInputBox.Show("Enter a new value", "Change Settings", "Default");
XtraInputBox.Show(this, "Enter a new value", "Change Settings", "Default");

// Initialize a new XtraInputBoxArgs instance.
XtraInputBoxArgs args = new XtraInputBoxArgs();
// Specify settings.
args.Caption = "Shipping options";
args.Prompt = "Delivery date";
args.DefaultButtonIndex = 0;
// Initialize a new DateEdit instance.
DateEdit editor = new DateEdit();
// Specify settings.
editor.Properties.CalendarView = DevExpress.XtraEditors.Repository.CalendarView.TouchUI;
editor.Properties.Mask.EditMask = "MMMM d, yyyy";
// Assign the editor to the input box settings.
args.Editor = editor;
// Specify the editor's default value.
args.DefaultResponse = DateTime.Now.Date.AddDays(3);
// Display an input box and assign the result to a variable.
var result = XtraInputBox.Show(args);

// You can also use the generic method and specify the return value's type.
DateTime resultDateTime = XtraInputBox.Show<DateTime>(args);
See Also