XtraInputBox.Show(String, String, String, MessageBoxButtons) Method

Displays an input box with the specified title, prompt, default response, and buttons.

Namespace: DevExpress.XtraEditors

Assembly: DevExpress.XtraEditors.v20.1.dll

Declaration

public static string Show(
    string prompt,
    string title,
    string defaultResponse,
    MessageBoxButtons buttons
)
Public Shared Function Show(
    prompt As String,
    title As String,
    defaultResponse As String,
    buttons As MessageBoxButtons
) As String

Parameters

Name Type Description
prompt String

The text above the editor.

title String

The text in the title bar.

defaultResponse String

The text that is the editor's default value.

buttons MessageBoxButtons

A value that specifies which buttons to display in the input box.

Returns

Type Description
String

If OK or Yes is clicked, the editor's value. Otherwise, String.Empty.

Examples

The code snippet below shows how to display a dialog box with custom settings.

using DevExpress.XtraEditors;

// Display an iput box with the specifiedx prompt, title, and default response.
XtraInputBox.Show("Enter a new value", "Change Settings", "Default");
XtraInputBox.Show(this, "Enter a new value", "Change Settings", "Default");

// Initialize a new XtraInputBoxArgs instance.
XtraInputBoxArgs args = new XtraInputBoxArgs();
// Specify settings.
args.Caption = "Shipping options";
args.Prompt = "Delivery date";
args.DefaultButtonIndex = 0;
// Initialize a new DateEdit instance.
DateEdit editor = new DateEdit();
// Specify settings.
editor.Properties.CalendarView = DevExpress.XtraEditors.Repository.CalendarView.TouchUI;
editor.Properties.Mask.EditMask = "MMMM d, yyyy";
// Assign the editor to the input box settings.
args.Editor = editor;
// Specify the editor's default value.
args.DefaultResponse = DateTime.Now.Date.AddDays(3);
// Display an input box and assign the result to a variable.
var result = XtraInputBox.Show(args);

// You can also use the generic method and specify the return value's type.
DateTime resultDateTime = XtraInputBox.Show<DateTime>(args);
See Also