How to: Sort Qualitative Scale Values in a Custom Sort Order

• Jun 07, 2019
• 2 minutes to read

To implement a custom qualitative scale values sort order, assign an object of a class implementing the IComparer interface to the AxisBase.QualitativeScaleComparer property.

View Example

MainWindow.xaml

<dxc:XYDiagram2D.AxisX>
    <dxc:AxisX2D>
        <dxc:AxisX2D.QualitativeScaleComparer>
            <local:NumberComparer/>
        </dxc:AxisX2D.QualitativeScaleComparer>
    </dxc:AxisX2D>
</dxc:XYDiagram2D.AxisX>

NumberComparer.cs

using System;
using System.Collections;

namespace CustomSortOrder {
    class NumberComparer : IComparer {
        public int Compare(object x, object y) {
            int iX = NumberConverter.ToInt(x);
            int iY = NumberConverter.ToInt(y);
            return iX - iY;
        }
    }

    class NumberConverter {
        public static int ToInt(object o) {
            string stringNumber = o as string;
            int number = 0;
            if (stringNumber == null) return -1;
            if (Int32.TryParse(stringNumber, out number))
                return number;
            switch (stringNumber.ToLower()) {
                case "one": return 1;
                case "two": return 2;
                case "three": return 3;
            }
            return number;
        }
    }
}

NumberComparer.vb

Imports System
Imports System.Collections

Namespace CustomSortOrder
    Friend Class NumberComparer
        Implements IComparer

        Public Function Compare(ByVal x As Object, ByVal y As Object) As Integer Implements IComparer.Compare
            Dim iX As Integer = NumberConverter.ToInt(x)
            Dim iY As Integer = NumberConverter.ToInt(y)
            Return iX - iY
        End Function
    End Class

    Friend Class NumberConverter
        Public Shared Function ToInt(ByVal o As Object) As Integer
            Dim stringNumber As String = TryCast(o, String)
            Dim number As Integer = 0
            If stringNumber Is Nothing Then
                Return -1
            End If
            If Int32.TryParse(stringNumber, number) Then
                Return number
            End If
            Select Case stringNumber.ToLower()
                Case "one"
                    Return 1
                Case "two"
                    Return 2
                Case "three"
                    Return 3
            End Select
            Return number
        End Function
    End Class
End Namespace